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Home » æ±è§£æ¹ç¨ \(3^2x = 81\) ç \(x\)ã - Aurero

æ±è§£æ¹ç¨ \(3^2x = 81\) ç \(x\)ã - Aurero

📅 March 14, 2026 👤 scraface

Mar 14, 2026

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📌 x + y = \pm 10

📌 Now compute \( x^2 - y^2 = (x - y)(x + y) \):

📌 If \( x + y = 10 \), then \( x^2 - y^2 = 4 \cdot 10 = 40 \)

📌 If \( x + y = -10 \), then \( x^2 - y^2 = 4 \cdot (-10) = -40 \)

📌 But from \( x - y = 4 \) and \( x^2 + y^2 = 58 \), suppose \( x + y = 10 \):

📌 Then solving \( x - y = 4 \), \( x + y = 10 \), add: \( 2x = 14 \Rightarrow x = 7 \), \( y = 3 \)

📌 Check: \( x^2 + y^2 = 49 + 9 = 58 \) â

📌 Then \( x^2 - y^2 = 49 - 9 = 40 \)

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