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Home » \[ k = 2\left(\frac2711\right) - 4 \] - Aurero

\[ k = 2\left(\frac2711\right) - 4 \] - Aurero

📅 March 13, 2026 👤 scraface

Mar 13, 2026

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Volume = \( 3x \cdot x \cdot 2x = 6x^3 \)
6x^3 = 108 \Rightarrow x^3 = 18 \Rightarrow x = \sqrt[3]{18}
x \approx 2.62 \quad \text{but exact form: } x = \sqrt[3]{18}
However, note \( 18 = 2 \cdot 3^2 \), so no perfect cube — but problem...
Check: \( 2.62^3 \approx 18 \)? Yes.
But since \( 6x^3 = 108 \Rightarrow x^3 = 18 \Rightarrow x = \sqrt[3]{...
So the width is \( \sqrt[3]{18} \) meters.
But wait — factor:
\( 6x^3 = 108 \Rightarrow x^3 = 18 \Rightarrow x = \sqrt[3]{18} \)
Alternatively, check if integer solution: try \( x = 3 \):

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