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Home » \[ R = \fracv^2 \sin(2\theta)g \] - Aurero

\[ R = \fracv^2 \sin(2\theta)g \] - Aurero

📅 March 13, 2026 👤 scraface

Mar 13, 2026

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📌 Use Poisson distribution: λ = 2 × 3 = 6.

📌 P(X=1) = (e⁻⁶ × 6¹) / 1! ≈ (0.002478 × 6) / 1 ≈ 0.01487.

📌 But for exactness, use binomial: If daily crash rate is 2, then over 3 days λ = 6.

📌 P(X=1) = C(6,1) × (2/3)¹ × (1/3)⁵ → but this is not matching.

📌 Better: Let’s define daily crash rate λ = 2 per day. Over 3 days, λ_total = 6.

📌 P(X=1) = (e⁻⁶ × 6¹) / 1! ≈ 0.0149.

📌 But for simplicity, use exact value.

📌 #### 0.0149

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