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Home » \[ u^2 - 2u + 1 = (u - 1)^2 \] - Aurero

\[ u^2 - 2u + 1 = (u - 1)^2 \] - Aurero

📅 March 14, 2026 👤 scraface

Mar 14, 2026

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= \mathbf{i}(6 - 4) - \mathbf{j}(-4 - 1) + \mathbf{k}(8 + 3)
= \mathbf{i}(2) + \mathbf{j}(5) + \mathbf{k}(11)
= \begin{pmatrix} 2 \\ 5 \\ 11 \end{pmatrix}
Thus, the vector orthogonal to both $\mathbf{a}$ and $\mathbf{b}$ is:
\boxed{\begin{pmatrix} 2 \\ 5 \\ 11 \end{pmatrix}}
An angel investor evaluates a biotech startup's growth vector $\mathbf...
To find the unit vector $\mathbf{u}$, compute the magnitude of $\mathb...
\|\mathbf{g}\| = \sqrt{7^2 + 24^2} = \sqrt{49 + 576} = \sqrt{625} = 25
The unit vector is:
\mathbf{u} = \frac{1}{\|\mathbf{g}\|} \mathbf{g} = \frac{1}{25} \begin...

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