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Home » Average speed: Total distance / Total time = 250 / 5.5 â 45.45 mph - Aurero

Average speed: Total distance / Total time = 250 / 5.5 â 45.45 mph - Aurero

📅 March 14, 2026 👤 scraface

Mar 14, 2026

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📝 Recent Posts

oxed{\sqrt{1 - rac{\sin^2 heta}{n^2}}}
An ichthyologist is modeling the movement of a fish in a 3D aquatic en...
The component of \(\mathbf{v}\) perpendicular to \(\mathbf{c}\) is giv...
\mathbf{v}_{\perp} = \mathbf{v} - ext{proj}_{\mathbf{c}} \mathbf{v}
where
ext{proj}_{\mathbf{c}} \mathbf{v} = \left( rac{\mathbf{v} \cdot \math...
ight) \mathbf{c}
First, compute the dot products:
\mathbf{v} \cdot \mathbf{c} = (2)(1) + (-1)(2) + (3)(-1) = 2 - 2 - 3 =...
\mathbf{c} \cdot \mathbf{c} = 1^2 + 2^2 + (-1)^2 = 1 + 4 + 1 = 6

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