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Home » Evaluate the integral \( \int (3x^2 - 2x + 1) \, dx \). - Aurero

Evaluate the integral \( \int (3x^2 - 2x + 1) \, dx \). - Aurero

📅 March 13, 2026 👤 scraface

Mar 13, 2026

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From (2): $w_1 = 3w_3 - 4$.
Substitute into (3):
-2(3w_3 - 4) - 3(-1 - 2w_3) = 2 \
-6w_3 + 8 + 3 + 6w_3 = 2 \Rightarrow 11 = 2
Contradiction. Hence, no such vector $\mathbf{w}$ exists.
oxed{ ext{No solution exists}}
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