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Home » \fraca + 4a + 3a + 4 + 1 + 73 = 15 - Aurero

\fraca + 4a + 3a + 4 + 1 + 73 = 15 - Aurero

📅 March 13, 2026 👤 scraface

Mar 13, 2026

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First, evaluate \( g(4) \):
g(4) = \sqrt{4 + 5} = \sqrt{9} = 3
Now compute \( f(g(4)) = f(3) \):
f(3) = 3(3) - 4 = 9 - 4 = 5
In a sustainability initiative, the amount of waste recycled \( R \) a...
R + C = 60
R^2 + C^2 = 2000
60^2 = 2000 + 2RC
= 2000 + 2RC
2RC = 1600 \quad \Rightarrow \quad RC = 800

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