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Home » $S(4,3) = 3 \cdot S(3,3) + S(3,2) = 3 \cdot 1 + 3 = 6$ - Aurero

$S(4,3) = 3 \cdot S(3,3) + S(3,2) = 3 \cdot 1 + 3 = 6$ - Aurero

📅 March 13, 2026 👤 scraface

Mar 13, 2026

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📌 Wir müssen überprüfen, ob alle Wurzeln \( w_i \) reell und positiv sind, da nur reelle positive \( w_i \) zu reellen \( v = w_i^2 \) führen. Wir analysieren das kubische Polynom \( f(w) = w^3 - 8w^2 + 9w - 18 \). Berechne Extremstellen:

📌 \( f'(w) = 3w^2 - 16w + 9 \). Diskriminante: \( 256 - 108 = 148 > 0 \), zwei kritische Punkte:

📌 \( w = \frac{16 \pm \sqrt{148}}{6} = \frac{16 \pm 2\sqrt{37}}{6} = \frac{8 \pm \sqrt{37}}{3} \).

📌 Approximiere \( \sqrt{37} \approx 6.08 \), also:

📌 \( w_1 \approx \frac{8 - 6.08}{3} \approx 0.64 \), \( w_2 \approx \frac{8 + 6.08}{3} \approx 4.69 \).

📌 Berechne \( f(0.64) \approx (0.64)^3 - 8(0.64)^2 + 9(0.64) - 18 \approx 0.26 - 3.26 + 5.76 - 18 \approx -15.24 < 0 \),

📌 \( f(4.69) \approx (4.69)^3 - 8(4.69)^2 + 9(4.69) - 18 \approx 102.7 - 175.6 + 42.2 - 18 \approx -49.7 < 0 \),

📌 und \( f(6) = 216 - 288 + 54 - 18 = -36 < 0 \), \( f(5) = 125 - 200 + 45 - 18 = -48 < 0 \), \( f(6.5) \approx 274.6 - 338 + 58.5 - 18 = -24.9 < 0 \), \( f(7) = 343 - 392 + 63 - 18 = 6 > 0 \).

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