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Home » \sqrt184 = \sqrt4 \times 46 = 2\sqrt46 - Aurero

\sqrt184 = \sqrt4 \times 46 = 2\sqrt46 - Aurero

📅 March 14, 2026 👤 scraface

Mar 14, 2026

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📝 Recent Posts

The minimum occurs when $ 2\sin x + 3\cos x $ is minimized, but since...
\min |2\sin x + 3\cos x + 4| = \min (2\sin x + 3\cos x + 4) = 4 - \sqr...
\min |2\sin x + 3\cos x + 4| = 4 - \sqrt{13} \quad \text{if } 4 - \sqr...
But $ 4 - \sqrt{13} > 0 $ since $ \sqrt{13} < 4 $, so yes.
But wait: is this the minimum? Since the expression inside is always g...
\min (2\sin x + 3\cos x + 4) = 4 + \min(2\sin x + 3\cos x) = 4 + (-\sq...
And since this value is positive, the absolute value does not introduc...
Thus, the minimum value is $ \boxed{4 - \sqrt{13}} $.
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