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Home » t = \frac{4 \pm \sqrt16 - 12}6 - Aurero

t = \frac{4 \pm \sqrt16 - 12}6 - Aurero

📅 March 14, 2026 👤 scraface

Mar 14, 2026

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= 1 \cdot 105 + 60
= 1 \cdot 60 + 45
= 1 \cdot 45 + 15
= 3 \cdot 15 + 0
عندما يصبح الباقي صفرًا، فإن القاسم المشترك الأكبر هو آخر باقي غير صفر...
إذن، $\gcd(105, 165) = \boxed{15}$.السؤال: أوجد مجموع جميع الزوايا $z...
الحل: لحل المعادلة $\sin(2z) = \frac{\sqrt{3}}{2}$، نحدد أولاً الزوايا...
2z = 60^\circ \quad \text{أو} \quad 2z = 120^\circ
بالقسمة على 2، نحصل على:
z = 30^\circ \quad \text{أو} \quad z = 60^\circ

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