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Home » We solve for $ k $: find the modular inverse of 7 modulo 13. - Aurero

We solve for $ k $: find the modular inverse of 7 modulo 13. - Aurero

📅 March 15, 2026 👤 scraface

Mar 15, 2026

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Discriminant: \( \Delta = (-5)^2 - 4(2)(-3) = 25 + 24 = 49 \).
\( x = rac{-(-5) \pm \sqrt{49}}{2(2)} = rac{5 \pm 7}{4} \).
So, \( x = rac{5 + 7}{4} = 3 \) or \( x = rac{5 - 7}{4} = -0.5 \).
The solutions are \( x = 3 \) and \( x = -0.5 \).
#### 3, -0.5
Question**: A train travels 300 km in 4 hours. If it increases its spe...
Original speed = \( rac{300 \, ext{km}}{4 \, ext{hr}} = 75 \) km/hr...
Increased speed = \( 75 + 0.25 imes 75 = 93.75 \) km/hr.
Time to travel 450 km = \( rac{450}{93.75} = 4.8 \) hours.
It will take 4.8 hours.

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